Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Vocabulary, Readiness & Video Check - Page 322: 9


1, 9

Work Step by Step

z^2+9=10z z^2-10z+9=0 Using ac method ac=9 b= -10 Two numbers are -9 and -1 then z^2-9z-z+9=0 z(z-9)-(z-9)=0 (z-1)(z-9)=0 z-1=0 z=1 z-9=0 z=9
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