Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Vocabulary, Readiness & Video Check - Page 322: 8


-2, 7/3

Work Step by Step

(3y^2-y-14)=0 Using ac method ac=-42 b= -1 Two numbers are -7 and 6 then (3y^2+6y-7y-14)=0 3y(y+2)-7(y+2)=0 (3y-7)(y+2)=0 3y-7=0 3y=7 y=7/3 y+2=0 y=-2
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