Work Step by Step
(3y^2-y-14)=0 Using ac method ac=-42 b= -1 Two numbers are -7 and 6 then (3y^2+6y-7y-14)=0 3y(y+2)-7(y+2)=0 (3y-7)(y+2)=0 3y-7=0 3y=7 y=7/3 y+2=0 y=-2
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