Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Vocabulary, Readiness & Video Check: 4


$c=\{ 2,4 \}$

Work Step by Step

By the Zero-Product Property, $ab=0$ implies $a=0 \text{ OR } b=0$. Hence, the solution to the given equation, $ (c-2)(c-4)=0 $, is \begin{array}{} c-2=0 \\ c=0+2 \\ c=2 ,\\\\\text{OR}\\\\ c-4=0 \\ c=0+4 \\ c=4 .\end{array} Hence, $ c=\{ 2,4 \} $.
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