## Intermediate Algebra (6th Edition)

$(3x-2)(4x-3)$
The two numbers whose product is $ac= 12(6)=72$ and whose sum is $b= -17$ are $\{ -8,-9 \}$. Using these two numbers to decompose the middle term, then the factored form of the expression, $12x^2-17x+6$, is \begin{array}{l}\require{cancel} 12x^2-8x-9x+6 \\\\= (12x^2-8x)-(9x-6) \\\\= 4x(3x-2)-3(3x-2) \\\\= (3x-2)(4x-3) .\end{array}