Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 303: 44



Work Step by Step

The two numbers whose product is $ac= 1(-100)=-100 $ and whose sum is $b= -48 $ are $\{ -50,2 \}$. Using these two numbers to decompose the middle term, then the factored form of the expression, $ x^2-48x-100 $, is \begin{array}{l}\require{cancel} x^2-50x+2x-100 \\\\= (x^2-50x)+(2x-100) \\\\= x(x-50)+2(x-50) \\\\= (x-50)(x+2) .\end{array}
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