Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 303: 16



Work Step by Step

The two numbers whose product is $ac= 3(4)=12 $ and whose sum is $b= 8 $ are $\{ 2,6 \}$. Using these two numbers to decompose the middle term, then the factored form of the given expression, $ 3x^2+8x+4 $,is \begin{array}{l}\require{cancel} 3x^2+2x+6x+4 \\\\= (3x^2+2x)+(6x+4) \\\\= x(3x+2)+2(3x+2) \\\\= (3x+2)(x+2) .\end{array}
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