Answer
$-x^{2}-6x+10$
Work Step by Step
We are given that $Q(x)=4x^{2}-6x+3$ and $R(x)=5x^{2}-7$.
$Q(x)-R(x)=(4x^{2}-6x+3)-(5x^{2}-7)=(4x^{2}-6x+3)+(-5x^{2}+7)$
Combine like terms.
$(4x^{2}-5x^{2})-6x+(3+7)=-x^{2}-6x+10$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set - Page 281: 113
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