## Intermediate Algebra (6th Edition)

$6x^{2}+14y$ units
We know that the perimeter of a rectangle is the sum of the length of its sides. Also, we know that a rectangle has 2 pairs of sides that are identical in length. Therefore, in order to find the perimeter of this rectangle, we can multiply each given side by 2 and sum the resulting products. $2\times(x+5y)+2\times(3x^{2}-x+2y)=2x+10y+6x^{2}-2x+4y$ Next, we can combine like terms to simplify. $6x^{2}+(2x-2x)+(10y+4y)=6x^{2}+14y$ units