Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review - Page 334: 48

Answer

$(a+3)(5a-1)$

Work Step by Step

Using factoring techniques, then, \begin{array}{l} 5a^2+14a-3 \\= 5a^2+15a-a-3 \\= 5a(a+3)-(a+3) \\= (a+3)(5a-1) .\end{array}
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