Answer
$\dfrac{y^{6}}{4}$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
(2x^0y^{-3})^{-2}
\\=
2^{-2}y^{-3(-2)}
\\=
2^{-2}y^{6}
\\\\=
\dfrac{y^{6}}{2^{2}}
\\\\=
\dfrac{y^{6}}{4}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Cumulative Review - Page 334: 39a
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