Answer
$\dfrac{27}{8}$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
\left( \dfrac{2}{3} \right)^{-3}
\\\\=
\left( \dfrac{3}{2} \right)^{3}
\\\\=
\dfrac{3^3}{2^3}
\\\\=
\dfrac{27}{8}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Cumulative Review - Page 334: 40c
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