Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Cumulative Review - Page 253: 42

Answer

$(-1,3)$

Work Step by Step

$5x+y=-2$ Equation $(1)$ $4x-2y=-10$ Equation $(2)$ Multiply Equation $(1)$ by $2$ and add with Equation $(2)$ $2(5x+y)+4x-2y=2(-2)-10$ $10x+2y+4x-2y=-4-10$ $14x=-14$ $x=-1$ Substituting $x$ value in Equation $(1)$ $5x+y=-2$ $5(-1)+y=-2$ $-5+y=-2$ $y=-2+5$ $y=3$ Solution: $(-1,3)$
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