Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Cumulative Review - Page 253: 41a

Answer

Yes, $(-1,1)$ is a solution.

Work Step by Step

Given Equations, $-x+y=2$ $2x-y=-3$ Substituting $x$ with $-1$ and $y$ with $1$, in each equation, $-x+y=2$ $-(-1)+1=2$ $1+1=2$ $2= 2$ True $2x-y=-3$ $2(-1)-1=-3$ $-2-1=-3$ $-3=-3$ True $(-1,1)$ satisfies both equations. So, it is the solution of the given equations.
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