Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Test - Page 198: 18


$L_{1}$ and $L_{2}$ are perpendicular lines.

Work Step by Step

Line $L_{1}$ has the equation $2x-5y=8$. Line $L_{2}$ passes through the points $(1,4)$ and $(-1,-1)$. Determine whether these lines are parallel lines, perpendicular lines or neither. Solve the equation of $L_{1}$ for $y$, to express it in slope-intercept form: $2x-5y=8$ $-5y=-2x+8$ $y=\dfrac{-2}{-5}x+\dfrac{8}{-5}$ $y=\dfrac{2}{5}x-\dfrac{8}{5}$ Since the slope-intercept form of the equation of a line is $y=mx+b$, where $m$ is the slope of the line and $b$ is its $y$-intercept, it can be seen from the equation obtained that the slope of $L_{1}$ is $m_{1}=\dfrac{2}{5}$. Use the formula for the slope of a line, which is $m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$, where $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are points through which it passes, to obtain the slope of $L_{2}$: $m_{2}=\dfrac{-1-4}{-1-1}=\dfrac{-5}{-2}=\dfrac{5}{2}$ It can be seen that $m_{2}$ is equal to $-\dfrac{1}{m_{1}}$. Because of this, it can be concluded that $L_{1}$ and $L_{2}$ are perpendicular lines.
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