Answer
y=-$\frac{1}{3}x$+$\frac{5}{3}$
Work Step by Step
(-1, 2); perpendicular to 3x-y=4
m=-$\frac{1}{3}$; (-1, 2)
y-2=-$\frac{1}{3}$(x-(-1))
3(y-2)=-1(x+1)
3y-6=-x-1
3y=-x+5
$\frac{3y}{3}$=$\frac{-x}{3}$+$\frac{5}{3}$
f(x)=-$\frac{1}{3}$+$\frac{5}{3}$
y=-$\frac{1}{3}$+$\frac{5}{3}$