Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Test - Page 198: 21

Answer

Please see the graph.

Work Step by Step

Blue line: $2x+4y<6$ Green line: $y\le-4$ Let's use the point $(0,0)$ to determine what sides of the lines to shade. Blue line: $2x+4y<6$ $2x+4y<6$ $2*0+4*0<6$ $0+0 < 6$ $0 < 6$ (true) Since this is true, then we will shade the side of the line with the point. We have a "less than" sign, so we'll use a dotted line to shade. Green line: $y\le-4$ $y\le-4$ $0 \le -4$ (false) Since this is false, then we will shade the side of the line without the point. We have a "less than or equal to" sign, so we'll use a solid line to shade. We want the intersection of the two graphs, so the intersection of the two graphs is the area of the graph that is green and blue.
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