## Intermediate Algebra (6th Edition)

The slope of the line is $\frac{6}{5}$ and the y-intercept is (0,6).
We are given that $-6x+5y=30$. We can transform this is equation into the slope-intercept form $y=mx+b$, where m is the slope of the line and the point (0,b) is the y-intercept. First, add 6x to both sides. $5y=6x+30$ Divide both sides by 5. $y=\frac{6}{5}x+6$ $m=\frac{6}{5}$ and $b=6$ Therefore, the slope of the line is $\frac{6}{5}$ and the y-intercept is (0,6).