Answer
The slope of the line is $\frac{2}{3}$ and the y-intercept is (0,$-\frac{10}{3}$)
Work Step by Step
We are given that $2x-3y=10$.
We can transform this equation into the slope-intercept form $y=mx+b$, where m is the slope and the point (0,b) is the y-intercept of the line.
First, subtract 2x from both sides.
$-3y=-2x+10$
Divide both sides by -3.
$y=\frac{2}{3}x-\frac{10}{3}$
$m=\frac{2}{3}$ and $b=-\frac{10}{3}$
Therefore, the slope of the line is $\frac{2}{3}$ and the y-intercept is (0,$-\frac{10}{3}$).