## Intermediate Algebra (6th Edition)

The slope of the line is $\frac{2}{3}$ and the y-intercept is (0,$-\frac{10}{3}$)
We are given that $2x-3y=10$. We can transform this equation into the slope-intercept form $y=mx+b$, where m is the slope and the point (0,b) is the y-intercept of the line. First, subtract 2x from both sides. $-3y=-2x+10$ Divide both sides by -3. $y=\frac{2}{3}x-\frac{10}{3}$ $m=\frac{2}{3}$ and $b=-\frac{10}{3}$ Therefore, the slope of the line is $\frac{2}{3}$ and the y-intercept is (0,$-\frac{10}{3}$).