## Intermediate Algebra (6th Edition)

$B∩D = \{ 5,7 \}$
$B = \{x|x$ is an odd integer $\}$ $= \{1,3,5,7,9,11,...... \}$ $D= \{ 4,5,6,7 \}$ Numbers $5$ and $7$ are in both sets B and D. Therefore, $B∩D = \{ 5,7 \}$