## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 2 - Section 2.5 - Compound Inequalities - Exercise Set - Page 94: 46

#### Answer

The solution is $\Big(-\infty,\dfrac{5}{7}\Big)$

#### Work Step by Step

$x\lt\dfrac{5}{7}$ and $x\lt1$ The interval that makes the first inequality true is $\Big(-\infty,\dfrac{5}{7}\Big)$ The interval that makes the second inequality true is $(-\infty,1)$ Since the compound inequality is formed by the word "and", the solution is formed by the numbers that satisfy both inequalities at the same time. The solution is $\Big(-\infty,\dfrac{5}{7}\Big)\cap(-\infty,1)$ or $\Big(-\infty,\dfrac{5}{7}\Big)$

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