## Intermediate Algebra (6th Edition)

The solution is $\Big(-\infty,\dfrac{5}{7}\Big)$
$x\lt\dfrac{5}{7}$ and $x\lt1$ The interval that makes the first inequality true is $\Big(-\infty,\dfrac{5}{7}\Big)$ The interval that makes the second inequality true is $(-\infty,1)$ Since the compound inequality is formed by the word "and", the solution is formed by the numbers that satisfy both inequalities at the same time. The solution is $\Big(-\infty,\dfrac{5}{7}\Big)\cap(-\infty,1)$ or $\Big(-\infty,\dfrac{5}{7}\Big)$