Answer
$\text{the interval } \left[ \dfrac{3}{2},6 \right]$
Work Step by Step
Using properties of inequality, then,
\begin{array}{l}
0\le2x-3\le9\\
0+3\le2x-3+3\le9+3\\
3\le2x\le12\\
\dfrac{3}{2}\le x\le6
.\end{array}
In interval notation, the solution is $
\text{the interval } \left[ \dfrac{3}{2},6 \right].
$
