Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Review - Page 113: 80

Answer

$\left( -3,3 \right)

Work Step by Step

Using the properties of equality, the given expression, $ 9+\left| 5x \right|\lt24 ,$ is equivalent to \begin{array}{l}\require{cancel} \left| 5x \right|\lt24-9 \\\\ \left| 5x \right|\lt15 .\end{array} Since for any $a\gt0$, $|x|\lt a$ implies $-a\lt x\lt a$, then the expression, $ \left| 5x \right|\lt15 ,$ is equivalent to \begin{array}{l}\require{cancel} -15\lt 5x\lt15 \\\\ -\dfrac{15}{5}\lt \dfrac{5}{5}x\lt\dfrac{15}{5} \\\\ -3\lt x\lt3 .\end{array} Hence, the solution set is $ \left( -3,3 \right) .$
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