Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Review - Page 113: 77

Answer

$\left( -\dfrac{8}{5},2 \right)$

Work Step by Step

Since for any $a\gt0$, $|x|\lt a$ implies $-a\lt x\lt a$, then the expression, $ \left| 5x-1 \right|\lt9 ,$ is equivalent to \begin{array}{l}\require{cancel} -9\lt 5x-1\lt9 \\\\ -9+1\lt 5x-1+1\lt9+1 \\\\ -8\lt 5x\lt10 \\\\ -\dfrac{8}{5}\lt \dfrac{5}{5}x\lt\dfrac{10}{5} \\\\ -\dfrac{8}{5}\lt x\lt2 .\end{array} Hence, the solution set is $ \left( -\dfrac{8}{5},2 \right) .$
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