Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Review - Page 113: 85



Work Step by Step

Multiplying both sides by the $LCD= 30 $, the given expression, $ \dfrac{x-2}{5}+\dfrac{x+2}{2}=\dfrac{x+4}{3} ,$ is equivalent to \begin{array}{l}\require{cancel} 6(x-2)+15(x+2)=10(x+4) \\\\ 6x-12+15x+30=10x+40 \\\\ 6x+15x-10x=40+12-30 \\\\ 11x=22 \\\\ x=\dfrac{22}{11} \\\\ x=2 .\end{array}
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