Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.2 - The Ellipse and the Hyperbola - Exercise Set - Page 618: 71

Answer

$$\frac{x^2}{1.69\times 10^{16}}+\frac{y^2}{1.5625\times10^{16}}=1$$

Work Step by Step

a = 130,000,000 b= 125,000,000 $$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$$ $$\frac{x^2}{1.69\times 10^{16}}+\frac{y^2}{1.5625\times10^{16}}=1$$
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