Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.2 - The Ellipse and the Hyperbola - Exercise Set - Page 618: 64h

Answer

$d=12$

Work Step by Step

$a^2=144$ $\sqrt {a^2} = \sqrt {144}$ $a = 12$ $b^2=140$ $\sqrt {b^2} = \sqrt {140}$ $b = \sqrt {140}$ $\sqrt {140} < 12$
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