Answer
See graph
Work Step by Step
$$y^2=x^2+16$$
$$y^2-x^2=16$$
$$\frac{y^2}{16}-\frac{x^2}{16}=1$$
This is a hyperbola with center (0,0). The corners of the box are (4,4), (4,-4), (-4,4), and (-4,-4). The vertices are (0,4) and (0,-4). Draw asymptotes through the corners of the box. Starting at (0,4) and (0,-4), draw two smooth curves that approach the asymptotes but never touch them.
