Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.1 - The Parabola and the Circle - Exercise Set - Page 610: 73

Answer

See graph

Work Step by Step

$$x^2-10y+y^2+4=0$$ $$x^2+y^2-10y=-4$$ Complete the square. $$x^2+y^2-10y+25=-4+25$$ $$x^2+(y-5)^2=21$$ This is a circle with center (0,5) with a radius of $\sqrt21$. Points are: $$(\sqrt21,5)$$ $$(-\sqrt21,5)$$ $$(0,5+\sqrt21)$$ $$(0,5-\sqrt21)$$ Approximate these values using a calculator, plot on a graph, and connect with a circle.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.