Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.1 - The Parabola and the Circle - Exercise Set - Page 610: 34

Answer

Center: $(-1,2)$ Radius: $\sqrt{5}$

Work Step by Step

$(x+1)^{2}+(y-2)^{2}=5$ The equation is given in the standard form, which is $(x-h)^{2}+(y-k)^{2}=r^{2}$, where $(h,k)$ is the center and $r$ is the radius So from the given equation, the center is $(-1,2)$ and the radius is $\sqrt{5}$
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