Answer
See graph
Work Step by Step
$$4(x+1)^2+4(y-3)^2=12$$
$$(x+1)^2+(y-3)^2=3$$
The center is (-1,3) and the radius is $\sqrt3$.
Points to plot are:
$$(-1+\sqrt3,3)$$
$$(-1-\sqrt3,3)$$
$$(-1,3+\sqrt3)$$
$$(-1,3-\sqrt3)$$
Approximate these values, plot these points and connect with a circle.
