Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 91

Answer

5

Work Step by Step

First we have to plug in the values that are given $\frac{3+2 |9--2|}{9+2(-2)}$ After this, first thing we do on the top is add that 9 and 2 since it is inside the absolute value $\frac{3+2 |11|}{9+2(-2)}$ Then we multiply and add (remember multiplication is always first before addition) $\frac{25}{9+2(-2)}$ We first do the multiplication $\frac{25}{9+-4}$ Then we add $\frac{25}{5}$ And finally divide the improper fraction The result is 5.
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