Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set - Page 28: 84

Answer

$$ \frac{2}{3}$$

Work Step by Step

We have $\frac{(-2)^4+3\sqrt {120-20}}{4^3+|5(-1)|}$ Solving $$\frac{16+3\sqrt {100}}{64+|-5|}$$ $$\frac{16+3*10}{64+5}$$ $$\frac{46}{69} = \frac{2}{3}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.