Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 74



Work Step by Step

$\frac{-\sqrt 16-(6-2.4)}{-2}=\frac{-4-(3.6)}{-2}=\frac{-(4+3.6)}{-2}=\frac{-7.6}{-2}=3.8$ We know that $\sqrt 16=4$, because $4^{2}=4\times4=16$
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