Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Appendix C - C - Exercise Set - Page 686: 34

Answer

$$x=5,y=-2,z=0$$

Work Step by Step

We solve the given system of equations using Cramer's Rule. To do this, we turn the system into two matrices. We then create x, y, and z matrices by replacing the values in the original matrix with corresponding columns in the answer matrix. We then find determinants to solve. Doing this, we find: $$ M=\begin{pmatrix}4&5&0\\ 0&3&2\\ 1&1&1\end{pmatrix} \\ M_2 = \begin{pmatrix}10\\ -6\\ 3\end{pmatrix} $$ Thus: $$ M_x=\begin{pmatrix}10&5&0\\ -6&3&2\\ 3&1&1\end{pmatrix} \\ M_y=\begin{pmatrix}4&10&0\\ 0&-6&2\\ 1&3&1\end{pmatrix} \\ M_z=\begin{pmatrix}4&5&10\\ 0&3&-6\\ 1&1&3\end{pmatrix} $$ Hence: $$ x=\frac{D_x}{D}=\frac{70}{14} =5 \\ y=\frac{D_y}{D}=\frac{-28}{14} =-2 \\ z=\frac{D_z}{D}=\frac{0}{14} =0 $$
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