Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Appendix C - C - Exercise Set: 36



Work Step by Step

A 2x2 determinant can be calculated as ad−bc, where a is the upper-left entry, b is the upper-right entry, c is the lower-left entry, and d is the lower-right entry. Therefore, the value of this determinant is $(6\times x)-(1\times-2)=26$ We can now solve this value for x. $6x-(-2)=6x+2=26$ Subtract 2 from both sides. $6x=24$ Divide both sides by 6. $x=4$
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