Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Appendix C - C - Exercise Set - Page 686: 10

Answer

Volume = $18 \text{ ft}^3$ Surface Area = $42 \text{ ft}^2$

Work Step by Step

The dimensions of the given figure are $3\text{ ft} \times 2\text{ ft} \times 3\text{ ft}$. Thus, its volume $V$ is: $V=lwh=3(2)(3) \text{ ft}^3 = 18 \text{ ft}^3$ The surface area $(S.A.)$of the figure is given by the formula: $S.A.=2lw + 2lh + 2wh \\S.A.=2(3)(2) + 2(3)(3) +2(2)(3) \\S.A.=12+18+12 \\S.A. = 42$ Thus, the surface area of the given figure is $42$ square feet.
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