Answer
$log_{3}7-log_{3}5$
Work Step by Step
We know that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{3}\frac{7}{5}=log_{3}7-log_{3}5$.
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