Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.7 - Complex Numbers - 7.7 Exercises - Page 491: 43



Work Step by Step

$\bf{\text{Solution Outline:}}$ To simplify the given expression, $ [(7+3i)-(4-2i)]+(3+i) ,$ remove the grouping symbols first. Then combine the real numbers and combine the imaginary numbers $\bf{\text{Solution Details:}}$ Removing the grouping symbols, the expression above is equivalent to \begin{array}{l}\require{cancel} [7+3i-4+2i]+(3+i) \\\\= 7+3i-4+2i+3+i .\end{array} Combining the real numbers and combining the imaginary numbers result to \begin{array}{l}\require{cancel} (7-4+3)+(3i+2i+i) \\\\= 6+6i .\end{array}
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