## Intermediate Algebra (12th Edition)

$6+6i$
$\bf{\text{Solution Outline:}}$ To simplify the given expression, $[(7+3i)-(4-2i)]+(3+i) ,$ remove the grouping symbols first. Then combine the real numbers and combine the imaginary numbers $\bf{\text{Solution Details:}}$ Removing the grouping symbols, the expression above is equivalent to \begin{array}{l}\require{cancel} [7+3i-4+2i]+(3+i) \\\\= 7+3i-4+2i+3+i .\end{array} Combining the real numbers and combining the imaginary numbers result to \begin{array}{l}\require{cancel} (7-4+3)+(3i+2i+i) \\\\= 6+6i .\end{array}