## Intermediate Algebra (12th Edition)

$4+8i$
$\bf{\text{Solution Outline:}}$ To simplify the given expression, $(-1+i)+(2+5i)+(3+2i) ,$ remove the grouping symbols first. Then combine the real numbers and combine the imaginary numbers $\bf{\text{Solution Details:}}$ Removing the grouping symbols, the expression above is equivalent to \begin{array}{l}\require{cancel} -1+i+2+5i+3+2i .\end{array} Combining the real numbers and combining the imaginary numbers result to \begin{array}{l}\require{cancel} (-1+2+3)+(i+5i+2i) \\\\= 4+8i .\end{array}