Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.7 - Complex Numbers - 7.7 Exercises - Page 491: 27


$\sqrt 3$

Work Step by Step

$\frac{\sqrt -300}{\sqrt -100}=\frac{i\sqrt 300}{i\sqrt 100}=\frac{i}{i}\times\frac{\sqrt 300}{\sqrt 100}=1\times\sqrt\frac{300}{100}=\sqrt\frac{300}{100}=\sqrt 3$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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