## Intermediate Algebra (12th Edition)

$\dfrac{-4\sqrt{13m}}{m}$
$\bf{\text{Solution Outline:}}$ To rationalize the given radical expression, $\dfrac{-4\sqrt{13}}{\sqrt{m}} ,$ multiply both the numerator and the denominator by the expression equal to the denominator. $\bf{\text{Solution Details:}}$ Multiplying both the numerator and the denominator by the expression equal to the denominator results to \begin{array}{l}\require{cancel} \dfrac{-4\sqrt{13}}{\sqrt{m}}\cdot\dfrac{\sqrt{m}}{\sqrt{m}} \\\\= \dfrac{-4\sqrt{13}(\sqrt{m})}{(\sqrt{m})^2} \\\\= \dfrac{-4\sqrt{13}(\sqrt{m})}{m} .\end{array} Using the Product Rule of radicals which is given by $\sqrt[m]{x}\cdot\sqrt[m]{y}=\sqrt[m]{xy},$ the expression above is equivalent to\begin{array}{l}\require{cancel} \dfrac{-4\sqrt{13(m)}}{m} \\\\= \dfrac{-4\sqrt{13m}}{m} .\end{array}