Answer
$\sqrt[3]{9}-36$
Work Step by Step
$\bf{\text{Solution Outline:}}$
To simplify the given radical expression, $ (\sqrt[3]{3}+6)(\sqrt[3]{3}-6)
,$ use the special product of the sum and difference of like terms.
$\bf{\text{Solution Details:}}$
Using the product of the sum and difference of like terms which is given by $(a+b)(a-b)=a^2-b^2,$ the expression above is equivalent
\begin{array}{l}\require{cancel}
(\sqrt[3]{3})^2-(6)^2
\\\\=
\sqrt[3]{(3)^2}-36
\\\\=
\sqrt[3]{9}-36
.\end{array}