## Intermediate Algebra (12th Edition)

$6$
$\bf{\text{Solution Outline:}}$ To simplify the given radical expression, $(\sqrt{8}-\sqrt{2})(\sqrt{8}+\sqrt{2}) ,$ use the special product on multiplying the sum and difference of like terms. $\bf{\text{Solution Details:}}$ Using the product of the sum and difference of like terms which is given by $(a+b)(a-b)=a^2-b^2,$ the expression above is equivalent \begin{array}{l}\require{cancel} (\sqrt{8})^2-(\sqrt{2})^2 \\\\= 8-2 \\\\= 6 .\end{array}