Answer
$
33.6^\circ F
$; approximately equal to the temperature on the given table
Work Step by Step
Using the given formula, $
\text{Windchill}=35.74+0.6215T-35.75V^{4/25}+0.4275TV^{4/25}
$, with $T=40$ and $v=10$, then
\begin{align*}
\text{Windchill}&=
35.74+0.6215(40)-35.75(10)^{4/25}+0.4275(40)(10)^{4/25}
\\&\approx
33.6
.\end{align*}
Hence, the windchill temperature is approximately $
33.6^\circ F
$. This temperature is approximately equal to the temperature on the $2$nd row, $1$st column (equal to $
34
$) of the given table.
