Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises - Page 458: 1

Answer

Choice D

Work Step by Step

The number $128$ can be expressed as $64\times2$. The factor $64$ is equal to $8^2$ while the factor $2$ is already a prime number which does not contain a perfect square factor. Thus $64$ is the greatest perfect square factor of $128$. Hence, Choice D.
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