Answer
$
19.0^\circ F
$; same as the data in the given table
Work Step by Step
Using the given formula, $
\text{Windchill}=35.74+0.6215T-35.75V^{4/25}+0.4275TV^{4/25}
$, with $T=30$ and $v=15$, then
\begin{align*}
\text{Windchill}&=
35.74+0.6215(30)-35.75(15)^{4/25}+0.4275(30)(15)^{4/25}
\\&\approx
19.0
.\end{align*}
Hence, the windchill temperature is $
19.0^\circ F
$. This temperature is the same temperature on the $3$rd row, $2$nd column of the given table.