Answer
B. 8
Work Step by Step
We know that $\sqrt 64=8$, because $8^{2}=8\times8=64$.
We also know that $\sqrt 81=9$, because $9^{2}=9\times9=81$.
Therefore, $\sqrt 67.8$ must be between 8 and 9. Since $|67.8-64|
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises - Page 439: 8
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