Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises - Page 439: 7

Answer

C. 11

Work Step by Step

We know that $\sqrt 121=11$, because $11^{2}=11\times11=121$. We also know that $\sqrt 144=12$, because $12^{2}=12\times12=144$. Therefore, $\sqrt 123.5$ must be between 11 and 12. Since $|123.5-121|
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