Work Step by Step
We are given that the length and width of a rectangle are $\sqrt 26$ and $\sqrt 98$. Since 26 is close to 25, we can use the fact that $\sqrt 25=5$ to approximate $\sqrt 26$ as 5. Since 98 is close to 100, we can use the fact that $\sqrt 100=10$ to approximate $\sqrt 98$ as 10. Furthermore, we know that the formula for the perimeter of a rectangle is $2l+2w$. Using our approximations, $2l+2w=2\times5+2\times10=10+20=30$.