Answer
7
Work Step by Step
We are given that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$, if all indicated roots are real numbers.
Therefore, $49^{\frac{1}{2}}=\sqrt[2] 49^{1}=\sqrt 49=7$.
We know that $\sqrt 49=7$, because $7^{2}=49$.
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 7 - Review Exercises - Page 497: 23
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