#### Answer

7

#### Work Step by Step

We are given that $a^{\frac{m}{n}}=\sqrt[n] a^{m}=(\sqrt[n] a)^{m}$, if all indicated roots are real numbers.
Therefore, $49^{\frac{1}{2}}=\sqrt[2] 49^{1}=\sqrt 49=7$.
We know that $\sqrt 49=7$, because $7^{2}=49$.

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

7

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